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The HARDEST Puzzle Yet!

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  • This is how I did it because I got really mad XD 0+0+0≠6 1+1+1≠6 2+2+2=6 3x3-3=6 4+4+4≠6 5+5+5≠6 6+6-6=6 7+7+7≠6 8+8+8≠6 (sr)9x(sr)9+(sr)9=6 (sr means Square Root) - Austin Frey
  • When they mentioned factorals, I saw a lightbulb. I tried to do it before they said the answer, and 8 is the hardest. If I got something wrong, please remember this is supposed to be one of the hardest puzzles. (0!+0!+0!)! (1+1+1)! 2+2+2 3x3-3 4+4-(✓4) 5/5+5 6+6-6 7/7-7 (absolute value) ((✓(8+8))!/8)! (9+9)/(✓9) - Neo Torralba
  • Solution to all real numbers: (ln(sqrt(x))+ln(x))/ln(sqrt(sqrt(x)))=6 - Joost van Mil
  • I thought they couldn't use square roots as it has a implicit 2... But I could do all the numbers from 1 to 7 without sqrt =) the 4 was the most difficult. (4-(4/4))! = 3! = 6 - Tadashi Mori
  • I've done every number except zero.... (1+1+1)!=6 2+2+2=6 3!x(3/3)=6 4+4-√4=6 5+(5/5) 6+6-6=6 7-(7/7)=6 8-√(√(8+8))=6 √9+(√9)x9=6 How eight works... 8+8=16, √16=4, √4=2, 8-2=6.. How nine works.. √9=3, 3x9=27, 27+9=36.. and √ of 36 equals 6!!!! It took me around 15 minutes to work this out.. I am 15 and I used to do a lot similar things in Intermediate..... I hope all the equations are right...  - Lizzie Song
  • ive got 7 of the 10 so far. im missing 0, 1, and 8.  - kellen liame
  • Extending the problem: what is the solution for 3 10's. Rules not splitting 1 and 0. 10 should be used as a whole. Also not the generic soln given by Joost - Dheerendra Kulkarni
  • I was able to do them in the first attempt. The only difference in my approach was in 8. 8-V(V(8+8) = 6 8-V(V16)=6 8-V(4)=6 8-2=6 6+6 So basically 8 is as simple as the others. I got stuck on 0 in the end but eventually got through that as well. :) - Prakhar Chanauria
  • This is like math for a 5th grade azn kid. Not even challenging a bit. Exaggerate much?  - Ellery Pham
  • I did it during the pause, and my processes were the same, except that for 8 I did 8-the square root of the square root of 8+8. - Jeikobu Kooruman
  • 8 is not the hardest. My son solved it before 0 or 1 and the solution is different then the one in the video. 8 - square root( square root( 8 + 8 ) ) - osgnuru
  • When they mentioned factorals, I saw a lightbulb. I tried to do it before they said the answer, and 8 is the hardest. If I got something wrong, please remember this is supposed to be one of the hardest puzzles. (0!+0!+0!)! (1+1+1)! 2+2+2 3x3-3 4+4-(✓4) 5/5+5 6+6-6 7/7-7 (absolute value) ((✓(8+8))!/8)! (9+9)/(✓9) - Pure Analysis
  • I found this amusing but not so hard after all. (Took me 4 minutes I think) (0! + 0! + 0!)! (1 + 1 + 1)! 2 + 2 + 2 3 * 3 - 3 4 + 4 - sqrt(4) 5 + (5 / 5) 6 + 6 - 6 7 - (7 / 7) 8 - sqrt(sqrt(8 + 8)) sqrt(9 * 9) - sqrt(9) - Martijn Courteaux
  • Honestly, just placing a slash through the equals sign is the easiest way to do that, because that indicates "is not equal to" and is well within the rules of using mathematical symbols - Dustmop Oelmann
  • cos(0) = 1 and use next line ┌tan(1)┐ + ┌tan(1)┐ + ┌tan(1)┐ 2 + 2 + 2 3! * (3/3) sqrt(4) + sqrt(4) + sqrt(4) 5 + (5/5) 6 + 6 - 6 7 - (7/7) └√8┘ + └√8┘ + └√8┘ (9+9)/√9 Now back to the video. I'm sure I broke some rule he forgot to introduce because this is too easy. - DarKMaTTeR
  • Well they did some of those better than I did, but I managed to come up with: (0! + 0! + 0!)! = 6 (1! + 1! + 1!)! = 6 2 + 2 + 2 = 6 (sqrt(3) * sqrt(3)) + 3 = 6 sqrt(4) + sqrt(4) + sqrt(4) = 6 5 + (5 / 5) = 6 6 * 6 / 6 = 6 7 - (7 / 7) = 6 8 - sqrt(sqrt(8 + 8)) = 6 (9 + 9) / sqrt(9) = 6 took about 25 minutes, though... - Joshua Hainge
  • you said you have to get the other to get the eights.Wrong because i got the eights without ones and twos (root(root(8)Xroot(8)))xroot(8) thinking in general that i need root(36) - manos mp
  • Pretty easy, except for 8. My solutions for 8: -(8 / .8 mod 8)=6 Here's how it works: 8/.8 = 10 10 mod 8 = 2 -2 (mod 8) = 6 Also, if you're a computer scientist and you use logs in base 2, log 8 = 3 so... log 8 times log 8 - log 8 = 6 (but that might be cheating, since "log" doesn't mean base 2 all the time... - Matthew Bloomfield
  • 9:58 he flicked off the dude - Duck wild
  • WHAT? I did Zero and One last, I don't understand your solution to 8. I did pause and I googled basic Maths Symbols so am I cheating? many years since I was at school :( (4+4) - sqrt4 ..... 8 - sqrt sqrt (8+8) I think I done good. - Qudos
  • +Kara Daviduik that would be adding an extra number though. which they couldn't - Ramhams1337
  • i did 8 differently 8 8+8=6 8 sqrt16=6 8 sqrt4=6 8-2=6 - thedarkswampert12345
  • 4 was easy. 4/.4-4. I did all except 1 and 8.  - Patrick Hanlon
  • Am I the only one who thought 8 was the easiest. If you do the sqrt of the sqrt of 8+8 you get 2 so 8- that gives you 6 - Shampoo8357
  • I tried for 5 minutes then gave up because it was so hard. - Kevin LoCascio
  • easier way for 8.... 8 - squareroot(squareroot(8 + 8)) squareroot(8+8) = 4 Squareroot(4) = 2 8 - 2 = 6 :) - mojave1981
  • The man in the red had wonted a high five but his friend just left him hanging lol - Diamond Whitehead
  • I got them all! (no really, if you want me to prove it, ask me to!) - Gary Lu
  • I used more factorials and cos(0) for the zeros (cos(0)+cos(0)+cos(0))! = 6 (1+1+1)! = 6 2*2+2 = 6 3-3+3! = 6 sqrt(4) + sqrt(4) + sqrt(4) = 6 (5/5) + 5 = 6 6+6-6 = 6 7-(7/7) = 6 sqrt((8/8) + 8)! = 6 9-9+sqrt(9)! = 6 - eternal kaori
  • There is a way to break the system if you use integrals. U can literally just take the integral of all of the numbers individually which gives u 0 0 0 and then u just do what u did with the actual 0s. - sean henderson
  • Also there happens to be another solution to 8 without factorials  - PenguinSparklez
  • how about 10? (log(10)+log(10)+log(10))! - Lauge Rønberg
  • additional solutions : ((sqrt(8+8))!/8)! =6 ((sqrt(9)*sqrt(9))/sqrt(9))! =6 (sqrt(10-(10/10)))! =6 - ero varuis
  • what about 8 - sqrt(sqrt(8+8)) = 6?? 8 - sqrt(sqrt(16)) = 8 - sqrt(4) = 8 - 2 = 6 - Rachael Putnam
  • I found a single solution for all, though it does use set theory: #({0,0,0})! I words that means the amount of elements in the collection {0,0,0} factorial. - Edekje
  • they also could have done cos(0) to make 1 instead of 0! - blingn007
  • uploader responding to comments regularly. subscribed. - SQUi5HiiFiSH
  • different way to do 8 is |√(√(8+8))-8| - Tom Kovar
  • solution for everything: count(n,n,n)! = 6 - Yeskt.com
  • It would be easier to do (8!-8)/8 - Complex Gaming
  • i'm going to do this to my math teacher who thinks i'm a dunbass - #chilling with da homies
  • I'm using scam school to get free pizza from my math teacher… putting bunch of stuff on notecards - Claire Williams
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